Wednesday, March 13, 2013

Chemistry

Chapter 8, 9
#8) a) Atoms go forth gain lose or share electrons to fulfill the nearest noble- ordnance electron configuration. Except for H and He. Electrons in the valence shell is called octet rule.
b) Sulfur atom has 6 valence electrons, it must gain 2 electrons to achieve an octet rule.
c) nitrogen has 5 valence electrons, so it should gain 3 more(prenominal) to achieve on octet.
#12) a)

#18)a) Zn2+ = [Ar] 3d10b) [Xe] noble gas configuration
c) [Ar] noble gas configurationd)[Kr] 4d6
e) [Xe] 4f14 5d106s2 f)[Xe] 4f14 5d106s2
#28) MgCl2 2326 kj, SrCl2 2127 kj, CaCl2 will be in the rage 2200-2250
b) ?H latt 795.8 kj + 179.3 kj +2(121.7 kj) + 590 kj= 2256 kj
#32)

#42) a) Br is more electronegative and it has stronger attraction for the shared electrons and will have partial negative charge.
B)Q= Mr=1.21 D2.49 A * 1 A1*10-9 m * 3.34*10^-301 D * 1 e1.60*10-19 C = 0.101 e so the charges are 0.101 e
#48) a)

b) Oxidation number for F is -1, and for P is +3
c) P has 0 formal charge, F has 0 formal charge.
d) No its not the same, P has oxidation number + 3 and formal charge 0
#52) More than one Lewis structure is drown, that is why resonance structure are needed to be more accurate.

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C) CO2 is common
#62) a)

b)

c)

D)
e)

#66)

?H = 3D(Câ€"H ) + D( Clâ€"Cl) D(Câ€"Cl) D( Hâ€"Cl) = 413 + 242 -328 -431 =-104 kj
b) ) ?H= 2( 259) + 2(366) -2(339)-2(276) = 20 kj

c) ) ?H= 163 +242 -2(200) = 5 kj

#72) i) ?H= 2(155) -4(485) = - 1630 kj

ii) ) ?H= 1072 +3(155) -4(485) -2( 190) = -780 kj

iii) ) ?H= 29 799) + 4( 155) -4( 475) -4( 190) = -482 kj

(i) is the most exothermic
b) the more oxygen bond to degree centigrade the less exothermic will be

Chapter 9

#16) a) 3 trigonal carpenters planeb) 4 tetrahedral
c) 5 trigonal bipyramidal d) 6 octahedral
#22) electron theatre tetrahedral. Molecular geometry trigonal pyramidal

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